You cant argue with that. Except shouldnt it be minus infinity to start with ?
dr. no on
July 17th, 2008 7:39 am
no
Theropes on
July 18th, 2008 5:47 pm
what a dumbass, I should tried to write this in my math tests just to see how the teacher reacts
ps :and it’s not minus infinity
Ian MacMillan on
July 27th, 2008 6:49 pm
um, as x approaches 8 from the left, the expression is always negative. As x gets close to 8 from the left, the value becomes extremely high, and negative, going to a limit of negative infinity. It approaches positive infinity as x approaches from the right, but this was not specified in the expression. And of course the expression is undefined at x=8. So, since I assume the default value would be for x approaching 8 from the left, why would the value not be negative infinity?
Ian on
July 28th, 2008 5:37 am
The result is beautiful in a way; One would have thought a marker with some sense of humour would have given a partial mark for original thinking. Actually, both expressions have no limit as x goes to “a”: (ie see Spivak, “Calculus”, Theorem 1)
Joe on
August 11th, 2008 7:08 pm
please explain to me how this formula or equasion benefits the life of yourself or myself in the future, coz im not seeing any
Kevin on
August 12th, 2008 1:06 pm
technically infinity is signless.
syn on
August 13th, 2008 4:13 am
um… the answer would be undefined. Although, the student’s answer is utterly brilliant.
Nikolai on
August 19th, 2008 1:02 am
it should be minus infinity… stupid teacher
joan on
September 9th, 2008 6:00 pm
the teacher only labeled the answer as wrong, and gave ir 0 points, he did’d say the answer was 0 xD
Numenaster on
October 2nd, 2008 10:51 am
The expression evaluates as undefined when x reaches 8 (in the top example) but but the limit is the value of the expression just a TEEEENY bit before 8 is reached. So infinity is correct.
Governator on
October 14th, 2008 5:21 pm
Actually, the limit of these expressions don’t exist. As x->8 from the left, it tends towards - infinity (yes, there is a distinction between - and + infinity, for all you commenting on it). As x->8 from the right, it tends towards + infinity. Since the limits for approaching from each individual direction are not equal, the overall limit, that is, lim (x->8); 1 / (x-8), does not exist. God, L2Calculus.
Governator on
October 14th, 2008 5:22 pm
doesn’t *
Maybe I should L2English.
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You cant argue with that. Except shouldnt it be minus infinity to start with ?
no
what a dumbass, I should tried to write this in my math tests just to see how the teacher reacts
ps :and it’s not minus infinity
um, as x approaches 8 from the left, the expression is always negative. As x gets close to 8 from the left, the value becomes extremely high, and negative, going to a limit of negative infinity. It approaches positive infinity as x approaches from the right, but this was not specified in the expression. And of course the expression is undefined at x=8. So, since I assume the default value would be for x approaching 8 from the left, why would the value not be negative infinity?
The result is beautiful in a way; One would have thought a marker with some sense of humour would have given a partial mark for original thinking. Actually, both expressions have no limit as x goes to “a”: (ie see Spivak, “Calculus”, Theorem 1)
please explain to me how this formula or equasion benefits the life of yourself or myself in the future, coz im not seeing any
technically infinity is signless.
um… the answer would be undefined. Although, the student’s answer is utterly brilliant.
it should be minus infinity… stupid teacher
the teacher only labeled the answer as wrong, and gave ir 0 points, he did’d say the answer was 0 xD
The expression evaluates as undefined when x reaches 8 (in the top example) but but the limit is the value of the expression just a TEEEENY bit before 8 is reached. So infinity is correct.
Actually, the limit of these expressions don’t exist. As x->8 from the left, it tends towards - infinity (yes, there is a distinction between - and + infinity, for all you commenting on it). As x->8 from the right, it tends towards + infinity. Since the limits for approaching from each individual direction are not equal, the overall limit, that is, lim (x->8); 1 / (x-8), does not exist. God, L2Calculus.
doesn’t *
Maybe I should L2English.